2x^2+0.24x-0.0144=0

Solution for 2x^2+0.24x-0.0144=0 equation:

2x^2+0.24x-0.0144=0

a = 2; b = 0.24; c = -0.0144;
Δ = b2-4ac
Δ = 0.242-4·2·(-0.0144)
Δ = 0.1728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.24)-\sqrt{0.1728}}{2*2}=\frac{-0.24-\sqrt{0.1728}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.24)+\sqrt{0.1728}}{2*2}=\frac{-0.24+\sqrt{0.1728}}{4}
$